Solve 8x=16x^2-32/2x-1

$$8 x = \frac { 16 x ^ { 2 } - 32 } { 2 x - 1 }$$

Solve for x

$$x=4$$

Steps for Solving Linear Equation

Variable x cannot be equal to \frac{1}{2} since division by zero is not defined. Multiply both sides of the equation by 2x-1.

$$8x\left(2x-1\right)=16x^{2}-32$$

Use the distributive property to multiply 8x by 2x-1.

$$16x^{2}-8x=16x^{2}-32$$

Subtract 16x^{2} from both sides.

$$16x^{2}-8x-16x^{2}=-32$$

Combine 16x^{2} and -16x^{2} to get 0.

$$-8x=-32$$

Divide both sides by -8.

$$x=\frac{-32}{-8}$$

Divide -32 by -8 to get 4.

$$x=4$$