Solve for x
x=-\frac{y}{2}+\frac{3}{4}
Solve for y
y=\frac{3}{2}-2x
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8x=6-4y
Subtract 4y from both sides.
\frac{8x}{8}=\frac{6-4y}{8}
Divide both sides by 8.
x=\frac{6-4y}{8}
Dividing by 8 undoes the multiplication by 8.
x=-\frac{y}{2}+\frac{3}{4}
Divide 6-4y by 8.
4y=6-8x
Subtract 8x from both sides.
\frac{4y}{4}=\frac{6-8x}{4}
Divide both sides by 4.
y=\frac{6-8x}{4}
Dividing by 4 undoes the multiplication by 4.
y=\frac{3}{2}-2x
Divide 6-8x by 4.
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