Solve 8x+4geq16+x+8+3x

$$8 x + 4 \geq 16 + x + 8 + 3 x$$

Solve for x

$$x\geq 5$$

Solution Steps

Add 16 and 8 to get 24.

$$8x+4\geq 24+x+3x$$

Combine x and 3x to get 4x.

$$8x+4\geq 24+4x$$

Subtract 4x from both sides.

$$8x+4-4x\geq 24$$

Combine 8x and -4x to get 4x.

$$4x+4\geq 24$$

Subtract 4 from both sides.

$$4x\geq 24-4$$

Subtract 4 from 24 to get 20.

$$4x\geq 20$$

Divide both sides by 4. Since 4 is positive, the inequality direction remains the same.

$$x\geq \frac{20}{4}$$

Divide 20 by 4 to get 5.

$$x\geq 5$$