Solve for x
x=-\frac{3y}{8}+\frac{9}{4}
Solve for y
y=-\frac{8x}{3}+6
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8x=18-3y
Subtract 3y from both sides.
\frac{8x}{8}=\frac{18-3y}{8}
Divide both sides by 8.
x=\frac{18-3y}{8}
Dividing by 8 undoes the multiplication by 8.
x=-\frac{3y}{8}+\frac{9}{4}
Divide 18-3y by 8.
3y=18-8x
Subtract 8x from both sides.
\frac{3y}{3}=\frac{18-8x}{3}
Divide both sides by 3.
y=\frac{18-8x}{3}
Dividing by 3 undoes the multiplication by 3.
y=-\frac{8x}{3}+6
Divide 18-8x by 3.
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