Solve 8x+3y+6=0

$$8 x + 3 y + 6 = 0$$

Solve for x

$$x=-\frac{3y}{8}-\frac{3}{4}$$

Steps for Solving Linear Equation

Subtract 3y from both sides. Anything subtracted from zero gives its negation.

$$8x+6=-3y$$

Subtract 6 from both sides.

$$8x=-3y-6$$

Divide both sides by 8.

$$\frac{8x}{8}=\frac{-3y-6}{8}$$

Dividing by 8 undoes the multiplication by 8.

$$x=\frac{-3y-6}{8}$$

Divide -3y-6 by 8.

$$x=-\frac{3y}{8}-\frac{3}{4}$$

Solve for y

$$y=-\frac{8x}{3}-2$$

Steps for Solving Linear Equation

Subtract 8x from both sides. Anything subtracted from zero gives its negation.

$$3y+6=-8x$$

Subtract 6 from both sides.

$$3y=-8x-6$$

Divide both sides by 3.

$$\frac{3y}{3}=\frac{-8x-6}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$y=\frac{-8x-6}{3}$$

Divide -8x-6 by 3.

$$y=-\frac{8x}{3}-2$$