Solve for x
x=\frac{-y-3}{4}
Solve for y
y=-4x-3
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8x=-6-2y
Subtract 2y from both sides.
8x=-2y-6
The equation is in standard form.
\frac{8x}{8}=\frac{-2y-6}{8}
Divide both sides by 8.
x=\frac{-2y-6}{8}
Dividing by 8 undoes the multiplication by 8.
x=\frac{-y-3}{4}
Divide -6-2y by 8.
2y=-6-8x
Subtract 8x from both sides.
2y=-8x-6
The equation is in standard form.
\frac{2y}{2}=\frac{-8x-6}{2}
Divide both sides by 2.
y=\frac{-8x-6}{2}
Dividing by 2 undoes the multiplication by 2.
y=-4x-3
Divide -6-8x by 2.
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