Solve 8x+2y+1=6xy+4

$$8 x + 2 y + 1 = 6 x y + 4$$

Solve for x

$$x=-\frac{2y-3}{2\left(4-3y\right)}$$

$$y\neq \frac{4}{3}$$

Steps for Solving Linear Equation

Subtract 6xy from both sides.

$$8x+2y+1-6xy=4$$

Subtract 2y from both sides.

$$8x+1-6xy=4-2y$$

Subtract 1 from both sides.

$$8x-6xy=4-2y-1$$

Subtract 1 from 4 to get 3.

$$8x-6xy=3-2y$$

Combine all terms containing x.

$$\left(8-6y\right)x=3-2y$$

Divide both sides by -6y+8.

$$\frac{\left(8-6y\right)x}{8-6y}=\frac{3-2y}{8-6y}$$

Dividing by -6y+8 undoes the multiplication by -6y+8.

$$x=\frac{3-2y}{8-6y}$$

Divide 3-2y by -6y+8.

$$x=\frac{3-2y}{2\left(4-3y\right)}$$

Solve for y

$$y=-\frac{8x-3}{2\left(1-3x\right)}$$

$$x\neq \frac{1}{3}$$

Steps for Solving Linear Equation

Subtract 6xy from both sides.

$$8x+2y+1-6xy=4$$

Subtract 8x from both sides.

$$2y+1-6xy=4-8x$$

Subtract 1 from both sides.

$$2y-6xy=4-8x-1$$

Subtract 1 from 4 to get 3.

$$2y-6xy=3-8x$$

Combine all terms containing y.

$$\left(2-6x\right)y=3-8x$$

Divide both sides by 2-6x.

$$\frac{\left(2-6x\right)y}{2-6x}=\frac{3-8x}{2-6x}$$

Dividing by 2-6x undoes the multiplication by 2-6x.

$$y=\frac{3-8x}{2-6x}$$

Divide 3-8x by 2-6x.

$$y=\frac{3-8x}{2\left(1-3x\right)}$$