Solve 8x+2geq-7x-7

$$8 x + 2 \geq - 7 x - 7$$

Solve for x

$$x\geq -\frac{3}{5}$$

Solution Steps

Add 7x to both sides.

$$8x+2+7x\geq -7$$

Combine 8x and 7x to get 15x.

$$15x+2\geq -7$$

Subtract 2 from both sides.

$$15x\geq -7-2$$

Subtract 2 from -7 to get -9.

$$15x\geq -9$$

Divide both sides by 15. Since 15 is positive, the inequality direction remains the same.

$$x\geq \frac{-9}{15}$$

Reduce the fraction \frac{-9}{15} to lowest terms by extracting and canceling out 3.

$$x\geq -\frac{3}{5}$$