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8x=\sqrt[3]{5}-2
Subtract 2 from both sides.
\frac{8x}{8}=\frac{\sqrt[3]{5}-2}{8}
Divide both sides by 8.
x=\frac{\sqrt[3]{5}-2}{8}
Dividing by 8 undoes the multiplication by 8.
x=\frac{\sqrt[3]{5}}{8}-\frac{1}{4}
Divide \sqrt[3]{5}-2 by 8.