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\left(z^{3}+2w^{3}\right)\left(z^{6}-2w^{3}z^{3}+4w^{6}\right)
Rewrite 8w^{9}+z^{9} as \left(z^{3}\right)^{3}+\left(2w^{3}\right)^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right).