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\left(2p+3q\right)\left(4p^{2}-6pq+9q^{2}\right)
Rewrite 8p^{3}+27q^{3} as \left(2p\right)^{3}+\left(3q\right)^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right).