Factor
2\left(2n+1\right)\left(2n^{2}+3\right)
Evaluate
2\left(2n+1\right)\left(2n^{2}+3\right)
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2\left(4n^{3}+2n^{2}+6n+3\right)
Factor out 2.
2n^{2}\left(2n+1\right)+3\left(2n+1\right)
Consider 4n^{3}+2n^{2}+6n+3. Do the grouping 4n^{3}+2n^{2}+6n+3=\left(4n^{3}+2n^{2}\right)+\left(6n+3\right), and factor out 2n^{2} in the first and 3 in the second group.
\left(2n+1\right)\left(2n^{2}+3\right)
Factor out common term 2n+1 by using distributive property.
2\left(2n+1\right)\left(2n^{2}+3\right)
Rewrite the complete factored expression. Polynomial 2n^{2}+3 is not factored since it does not have any rational roots.
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