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\left(-5y+2m\right)\left(25y^{2}+10my+4m^{2}\right)
Rewrite 8m^{3}-125y^{3} as \left(-5y\right)^{3}+\left(2m\right)^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right).