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\left(2a^{2}-3b^{2}\right)\left(4a^{4}+6a^{2}b^{2}+9b^{4}\right)
Rewrite 8a^{6}-27b^{6} as \left(2a^{2}\right)^{3}-\left(3b^{2}\right)^{3}. The difference of cubes can be factored using the rule: p^{3}-q^{3}=\left(p-q\right)\left(p^{2}+pq+q^{2}\right).