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\left(2a-5b\right)\left(4a^{2}+10ab+25b^{2}\right)
Rewrite 8a^{3}-125b^{3} as \left(2a\right)^{3}-\left(5b\right)^{3}. The difference of cubes can be factored using the rule: p^{3}-q^{3}=\left(p-q\right)\left(p^{2}+pq+q^{2}\right).