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8a^{2}-22a-2=0
Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.
a=\frac{-\left(-22\right)±\sqrt{\left(-22\right)^{2}-4\times 8\left(-2\right)}}{2\times 8}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
a=\frac{-\left(-22\right)±\sqrt{484-4\times 8\left(-2\right)}}{2\times 8}
Square -22.
a=\frac{-\left(-22\right)±\sqrt{484-32\left(-2\right)}}{2\times 8}
Multiply -4 times 8.
a=\frac{-\left(-22\right)±\sqrt{484+64}}{2\times 8}
Multiply -32 times -2.
a=\frac{-\left(-22\right)±\sqrt{548}}{2\times 8}
Add 484 to 64.
a=\frac{-\left(-22\right)±2\sqrt{137}}{2\times 8}
Take the square root of 548.
a=\frac{22±2\sqrt{137}}{2\times 8}
The opposite of -22 is 22.
a=\frac{22±2\sqrt{137}}{16}
Multiply 2 times 8.
a=\frac{2\sqrt{137}+22}{16}
Now solve the equation a=\frac{22±2\sqrt{137}}{16} when ± is plus. Add 22 to 2\sqrt{137}.
a=\frac{\sqrt{137}+11}{8}
Divide 22+2\sqrt{137} by 16.
a=\frac{22-2\sqrt{137}}{16}
Now solve the equation a=\frac{22±2\sqrt{137}}{16} when ± is minus. Subtract 2\sqrt{137} from 22.
a=\frac{11-\sqrt{137}}{8}
Divide 22-2\sqrt{137} by 16.
8a^{2}-22a-2=8\left(a-\frac{\sqrt{137}+11}{8}\right)\left(a-\frac{11-\sqrt{137}}{8}\right)
Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute \frac{11+\sqrt{137}}{8} for x_{1} and \frac{11-\sqrt{137}}{8} for x_{2}.
x ^ 2 -\frac{11}{4}x -\frac{1}{4} = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.This is achieved by dividing both sides of the equation by 8
r + s = \frac{11}{4} rs = -\frac{1}{4}
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = \frac{11}{8} - u s = \frac{11}{8} + u
Two numbers r and s sum up to \frac{11}{4} exactly when the average of the two numbers is \frac{1}{2}*\frac{11}{4} = \frac{11}{8}. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(\frac{11}{8} - u) (\frac{11}{8} + u) = -\frac{1}{4}
To solve for unknown quantity u, substitute these in the product equation rs = -\frac{1}{4}
\frac{121}{64} - u^2 = -\frac{1}{4}
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = -\frac{1}{4}-\frac{121}{64} = -\frac{137}{64}
Simplify the expression by subtracting \frac{121}{64} on both sides
u^2 = \frac{137}{64} u = \pm\sqrt{\frac{137}{64}} = \pm \frac{\sqrt{137}}{8}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =\frac{11}{8} - \frac{\sqrt{137}}{8} = -0.088 s = \frac{11}{8} + \frac{\sqrt{137}}{8} = 2.838
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.