Solve 8B+10C=4

$$8 B + 10 C = 4$$

Solve for B

$$B=-\frac{5C}{4}+\frac{1}{2}$$

Steps for Solving Linear Equation

Subtract 10C from both sides.

$$8B=4-10C$$

Divide both sides by 8.

$$\frac{8B}{8}=\frac{4-10C}{8}$$

Dividing by 8 undoes the multiplication by 8.

$$B=\frac{4-10C}{8}$$

Divide 4-10C by 8.

$$B=-\frac{5C}{4}+\frac{1}{2}$$

Solve for C

$$C=\frac{2-4B}{5}$$

Steps for Solving Linear Equation

Subtract 8B from both sides.

$$10C=4-8B$$

Divide both sides by 10.

$$\frac{10C}{10}=\frac{4-8B}{10}$$

Dividing by 10 undoes the multiplication by 10.

$$C=\frac{4-8B}{10}$$

Divide 4-8B by 10.

$$C=\frac{2-4B}{5}$$