Solve for x
x\leq 3
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8-3x-x\geq -4
Subtract x from both sides.
8-4x\geq -4
Combine -3x and -x to get -4x.
-4x\geq -4-8
Subtract 8 from both sides.
-4x\geq -12
Subtract 8 from -4 to get -12.
x\leq \frac{-12}{-4}
Divide both sides by -4. Since -4 is negative, the inequality direction is changed.
x\leq 3
Divide -12 by -4 to get 3.
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Simultaneous equation
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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