Solve 8-3^2+(8-2-7)^2-(6-3-4)^3

$$8 - 3 ^ { 2 } + ( 8 - 2 - 7 ) ^ { 2 } - ( 6 - 3 - 4 ) ^ { 3 }$$

Evaluate

$$1$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$8-9+\left(8-2-7\right)^{2}-\left(6-3-4\right)^{3}$$

Subtract 9 from 8 to get -1.

$$-1+\left(8-2-7\right)^{2}-\left(6-3-4\right)^{3}$$

Subtract 2 from 8 to get 6.

$$-1+\left(6-7\right)^{2}-\left(6-3-4\right)^{3}$$

Subtract 7 from 6 to get -1.

$$-1+\left(-1\right)^{2}-\left(6-3-4\right)^{3}$$

Calculate -1 to the power of 2 and get 1.

$$-1+1-\left(6-3-4\right)^{3}$$

Add -1 and 1 to get 0.

$$0-\left(6-3-4\right)^{3}$$

Subtract 3 from 6 to get 3.

$$0-\left(3-4\right)^{3}$$

Subtract 4 from 3 to get -1.

$$0-\left(-1\right)^{3}$$

Calculate -1 to the power of 3 and get -1.

$$0-\left(-1\right)$$

The opposite of -1 is 1.

$$0+1$$

Add 0 and 1 to get 1.

$$1$$

Factor

$$1$$