Solve 8-sqrt{x+12}=3

$$8 - \sqrt { x + 12 } = 3$$

Solve for x

$$x=13$$

Steps for Solving Radical Equations

Subtract 8 from both sides of the equation.

$$-\sqrt{x+12}+8-8=3-8$$

Subtracting 8 from itself leaves 0.

$$-\sqrt{x+12}=3-8$$

Subtract 8 from 3.

$$-\sqrt{x+12}=-5$$

Divide both sides by -1.

$$\frac{-\sqrt{x+12}}{-1}=-\frac{5}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$\sqrt{x+12}=-\frac{5}{-1}$$

Divide -5 by -1.

$$\sqrt{x+12}=5$$

Square both sides of the equation.

$$x+12=25$$

Subtract 12 from both sides of the equation.

$$x+12-12=25-12$$

Subtracting 12 from itself leaves 0.

$$x=25-12$$

Subtract 12 from 25.

$$x=13$$