Solve 8(x+1)^2=7

$$8 ( x + 1 ) ^ { 2 } = 7$$

Solve for x

$$x=\frac{\sqrt{14}}{4}-1\approx -0.064585653$$

$$x=-\frac{\sqrt{14}}{4}-1\approx -1.935414347$$

Steps by Finding Square Root

Divide both sides by 8.

$$\frac{8\left(x+1\right)^{2}}{8}=\frac{7}{8}$$

Dividing by 8 undoes the multiplication by 8.

$$\left(x+1\right)^{2}=\frac{7}{8}$$

Take the square root of both sides of the equation.

$$x+1=\frac{\sqrt{14}}{4} x+1=-\frac{\sqrt{14}}{4}$$

Subtract 1 from both sides of the equation.

$$x+1-1=\frac{\sqrt{14}}{4}-1 x+1-1=-\frac{\sqrt{14}}{4}-1$$

Subtracting 1 from itself leaves 0.

$$x=\frac{\sqrt{14}}{4}-1 x=-\frac{\sqrt{14}}{4}-1$$