Solve 8(b+1)+4=3(2b-8)-16

$$8 ( b + 1 ) + 4 = 3 ( 2 b - 8 ) - 16$$

Solve for b

$$b=-26$$

Steps for Solving Linear Equation

Use the distributive property to multiply 8 by b+1.

$$8b+8+4=3\left(2b-8\right)-16$$

Add 8 and 4 to get 12.

$$8b+12=3\left(2b-8\right)-16$$

Use the distributive property to multiply 3 by 2b-8.

$$8b+12=6b-24-16$$

Subtract 16 from -24 to get -40.

$$8b+12=6b-40$$

Subtract 6b from both sides.

$$8b+12-6b=-40$$

Combine 8b and -6b to get 2b.

$$2b+12=-40$$

Subtract 12 from both sides.

$$2b=-40-12$$

Subtract 12 from -40 to get -52.

$$2b=-52$$

Divide both sides by 2.

$$b=\frac{-52}{2}$$

Divide -52 by 2 to get -26.

$$b=-26$$