Solve 8(9+1)(9^2+1)(9^4+1)(9^8+1)=

$$8 ( 9 + 1 ) ( 9 ^ { 2 } + 1 ) ( 9 ^ { 4 } + 1 ) ( 9 ^ { 8 } + 1 ) =$$

Evaluate

$$1853020188851840$$

Solution Steps

Add 9 and 1 to get 10.

$$8\times 10\left(9^{2}+1\right)\left(9^{4}+1\right)\left(9^{8}+1\right)$$

Multiply 8 and 10 to get 80.

$$80\left(9^{2}+1\right)\left(9^{4}+1\right)\left(9^{8}+1\right)$$

Calculate 9 to the power of 2 and get 81.

$$80\left(81+1\right)\left(9^{4}+1\right)\left(9^{8}+1\right)$$

Add 81 and 1 to get 82.

$$80\times 82\left(9^{4}+1\right)\left(9^{8}+1\right)$$

Multiply 80 and 82 to get 6560.

$$6560\left(9^{4}+1\right)\left(9^{8}+1\right)$$

Calculate 9 to the power of 4 and get 6561.

$$6560\left(6561+1\right)\left(9^{8}+1\right)$$

Add 6561 and 1 to get 6562.

$$6560\times 6562\left(9^{8}+1\right)$$

Multiply 6560 and 6562 to get 43046720.

$$43046720\left(9^{8}+1\right)$$

Calculate 9 to the power of 8 and get 43046721.

$$43046720\left(43046721+1\right)$$

Add 43046721 and 1 to get 43046722.

$$43046720\times 43046722$$

Multiply 43046720 and 43046722 to get 1853020188851840.

$$1853020188851840$$

Factor

$$2^{7}\times 5\times 17\times 41\times 193\times 21523361$$