Solve 8(3y)=xyz

$$8 ( 3 y ) = x y z$$

Solve for x

$$\left\{\begin{matrix}x=\frac{24}{z}\text{, }&z\neq 0\\x\in \mathrm{R}\text{, }&y=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply 8 and 3 to get 24.

$$24y=xyz$$

Swap sides so that all variable terms are on the left hand side.

$$xyz=24y$$

The equation is in standard form.

$$yzx=24y$$

Divide both sides by yz.

$$\frac{yzx}{yz}=\frac{24y}{yz}$$

Dividing by yz undoes the multiplication by yz.

$$x=\frac{24y}{yz}$$

Divide 24y by yz.

$$x=\frac{24}{z}$$

Solve for y

$$\left\{\begin{matrix}\\y=0\text{, }&\text{unconditionally}\\y\in \mathrm{R}\text{, }&x=\frac{24}{z}\text{ and }z\neq 0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply 8 and 3 to get 24.

$$24y=xyz$$

Subtract xyz from both sides.

$$24y-xyz=0$$

Reorder the terms.

$$-xyz+24y=0$$

Combine all terms containing y.

$$\left(-xz+24\right)y=0$$

The equation is in standard form.

$$\left(24-xz\right)y=0$$

Divide 0 by 24-xz.

$$y=0$$