Solve 8(1)^2(2)-2(1)(2)^2+8

$$8 ( 1 ) ^ { 2 } ( 2 ) - 2 ( 1 ) ( 2 ) ^ { 2 } + 8$$

Evaluate

$$16$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$8\times 1^{2}\times 2-2^{3}\times 1+8$$

Calculate 1 to the power of 2 and get 1.

$$8\times 1\times 2-2^{3}\times 1+8$$

Multiply 8 and 1 to get 8.

$$8\times 2-2^{3}\times 1+8$$

Multiply 8 and 2 to get 16.

$$16-2^{3}\times 1+8$$

Calculate 2 to the power of 3 and get 8.

$$16-8\times 1+8$$

Multiply 8 and 1 to get 8.

$$16-8+8$$

Subtract 8 from 16 to get 8.

$$8+8$$

Add 8 and 8 to get 16.

$$16$$

Factor

$$2^{4}$$