Solve 8(-2)^3-3^3+2^-3*2^7

$$8 ( - 2 ) ^ { 3 } - 3 ^ { 3 } + 2 ^ { - 3 } \times 2 ^ { 7 }$$

Evaluate

$$-75$$

Solution Steps

To multiply powers of the same base, add their exponents. Add -3 and 7 to get 4.

$$8\left(-2\right)^{3}-3^{3}+2^{4}$$

Calculate -2 to the power of 3 and get -8.

$$8\left(-8\right)-3^{3}+2^{4}$$

Multiply 8 and -8 to get -64.

$$-64-3^{3}+2^{4}$$

Calculate 3 to the power of 3 and get 27.

$$-64-27+2^{4}$$

Subtract 27 from -64 to get -91.

$$-91+2^{4}$$

Calculate 2 to the power of 4 and get 16.

$$-91+16$$

Add -91 and 16 to get -75.

$$-75$$

Factor

$$-75$$