Solve 8(2/3)^-1(6/4)(4/2)^-7

$$8 ( \frac { 2 } { 3 } ) ^ { - 1 } ( \frac { 6 } { 4 } ) ( \frac { 4 } { 2 } ) ^ { - 7 }$$

Evaluate

$$\frac{9}{64}=0.140625$$

Solution Steps

Calculate \frac{2}{3} to the power of -1 and get \frac{3}{2}.

$$8\times \frac{3}{2}\times \frac{6}{4}\times \left(\frac{4}{2}\right)^{-7}$$

Multiply 8 and \frac{3}{2} to get 12.

$$12\times \frac{6}{4}\times \left(\frac{4}{2}\right)^{-7}$$

Reduce the fraction \frac{6}{4} to lowest terms by extracting and canceling out 2.

$$12\times \frac{3}{2}\times \left(\frac{4}{2}\right)^{-7}$$

Multiply 12 and \frac{3}{2} to get 18.

$$18\times \left(\frac{4}{2}\right)^{-7}$$

Divide 4 by 2 to get 2.

$$18\times 2^{-7}$$

Calculate 2 to the power of -7 and get \frac{1}{128}.

$$18\times \frac{1}{128}$$

Multiply 18 and \frac{1}{128} to get \frac{9}{64}.

$$\frac{9}{64}$$

Factor

$$\frac{3 ^ {2}}{2 ^ {6}} = 0.140625$$