Factor
8\left(x-2\right)\left(x^{2}+2x+4\right)
Evaluate
8\left(x^{3}-8\right)
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8\left(x^{3}-8\right)
Factor out 8.
\left(x-2\right)\left(x^{2}+2x+4\right)
Consider x^{3}-8. Rewrite x^{3}-8 as x^{3}-2^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right).
8\left(x-2\right)\left(x^{2}+2x+4\right)
Rewrite the complete factored expression. Polynomial x^{2}+2x+4 is not factored since it does not have any rational roots.
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