Factor
\frac{\left(4x-y\right)\left(16x^{2}+4xy+y^{2}\right)}{8}
Evaluate
-\frac{y^{3}}{8}+8x^{3}
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\frac{64x^{3}-y^{3}}{8}
Factor out \frac{1}{8}.
\left(4x-y\right)\left(16x^{2}+4xy+y^{2}\right)
Consider 64x^{3}-y^{3}. Rewrite 64x^{3}-y^{3} as \left(4x\right)^{3}-y^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right).
\frac{\left(4x-y\right)\left(16x^{2}+4xy+y^{2}\right)}{8}
Rewrite the complete factored expression.
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Limits
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