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Solve for x (complex solution)
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8x^{2}+53=0
Subtract 2 from 55 to get 53.
8x^{2}=-53
Subtract 53 from both sides. Anything subtracted from zero gives its negation.
x^{2}=-\frac{53}{8}
Divide both sides by 8.
x=\frac{\sqrt{106}i}{4} x=-\frac{\sqrt{106}i}{4}
The equation is now solved.
8x^{2}+53=0
Subtract 2 from 55 to get 53.
x=\frac{0±\sqrt{0^{2}-4\times 8\times 53}}{2\times 8}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 8 for a, 0 for b, and 53 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 8\times 53}}{2\times 8}
Square 0.
x=\frac{0±\sqrt{-32\times 53}}{2\times 8}
Multiply -4 times 8.
x=\frac{0±\sqrt{-1696}}{2\times 8}
Multiply -32 times 53.
x=\frac{0±4\sqrt{106}i}{2\times 8}
Take the square root of -1696.
x=\frac{0±4\sqrt{106}i}{16}
Multiply 2 times 8.
x=\frac{\sqrt{106}i}{4}
Now solve the equation x=\frac{0±4\sqrt{106}i}{16} when ± is plus.
x=-\frac{\sqrt{106}i}{4}
Now solve the equation x=\frac{0±4\sqrt{106}i}{16} when ± is minus.
x=\frac{\sqrt{106}i}{4} x=-\frac{\sqrt{106}i}{4}
The equation is now solved.