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8x^{2}=54-3
Subtract 3 from both sides.
8x^{2}=51
Subtract 3 from 54 to get 51.
x^{2}=\frac{51}{8}
Divide both sides by 8.
x=\frac{\sqrt{102}}{4} x=-\frac{\sqrt{102}}{4}
Take the square root of both sides of the equation.
8x^{2}+3-54=0
Subtract 54 from both sides.
8x^{2}-51=0
Subtract 54 from 3 to get -51.
x=\frac{0±\sqrt{0^{2}-4\times 8\left(-51\right)}}{2\times 8}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 8 for a, 0 for b, and -51 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 8\left(-51\right)}}{2\times 8}
Square 0.
x=\frac{0±\sqrt{-32\left(-51\right)}}{2\times 8}
Multiply -4 times 8.
x=\frac{0±\sqrt{1632}}{2\times 8}
Multiply -32 times -51.
x=\frac{0±4\sqrt{102}}{2\times 8}
Take the square root of 1632.
x=\frac{0±4\sqrt{102}}{16}
Multiply 2 times 8.
x=\frac{\sqrt{102}}{4}
Now solve the equation x=\frac{0±4\sqrt{102}}{16} when ± is plus.
x=-\frac{\sqrt{102}}{4}
Now solve the equation x=\frac{0±4\sqrt{102}}{16} when ± is minus.
x=\frac{\sqrt{102}}{4} x=-\frac{\sqrt{102}}{4}
The equation is now solved.