Solve 82^20-2*20^2+8

$$8 { 2 }^{ 2 } 0-2 \cdot 2 { 0 }^{ 2 } +8$$

Evaluate

$$8$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$8\times 4\times 0-2\times 2\times 0^{2}+8$$

Multiply 8 and 4 to get 32.

$$32\times 0-2\times 2\times 0^{2}+8$$

Multiply 32 and 0 to get 0.

$$0-2\times 2\times 0^{2}+8$$

Multiply 2 and 2 to get 4.

$$0-4\times 0^{2}+8$$

Calculate 0 to the power of 2 and get 0.

$$0-4\times 0+8$$

Multiply 4 and 0 to get 0.

$$0-0+8$$

Subtracting 0 from itself leaves 0.

$$0+8$$

Add 0 and 8 to get 8.

$$8$$

Factor

$$2^{3}$$