Solve 8*143div7-20*(8.5div6)=

$$8 \times 143 \div 7 - 20 \times ( 8.5 \div 6 ) =$$

Evaluate

$$\frac{2837}{21}\approx 135.095238095$$

Solution Steps

Multiply 8 and 143 to get 1144.

$$\frac{1144}{7}-20\times \frac{8.5}{6}$$

Expand \frac{8.5}{6} by multiplying both numerator and the denominator by 10.

$$\frac{1144}{7}-20\times \frac{85}{60}$$

Reduce the fraction \frac{85}{60} to lowest terms by extracting and canceling out 5.

$$\frac{1144}{7}-20\times \frac{17}{12}$$

Express 20\times \frac{17}{12} as a single fraction.

$$\frac{1144}{7}-\frac{20\times 17}{12}$$

Multiply 20 and 17 to get 340.

$$\frac{1144}{7}-\frac{340}{12}$$

Reduce the fraction \frac{340}{12} to lowest terms by extracting and canceling out 4.

$$\frac{1144}{7}-\frac{85}{3}$$

Least common multiple of 7 and 3 is 21. Convert \frac{1144}{7} and \frac{85}{3} to fractions with denominator 21.

$$\frac{3432}{21}-\frac{595}{21}$$

Since \frac{3432}{21} and \frac{595}{21} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3432-595}{21}$$

Subtract 595 from 3432 to get 2837.

$$\frac{2837}{21}$$

Factor

$$\frac{2837}{3 \cdot 7} = 135\frac{2}{21} = 135.0952380952381$$