Solve 8*{(1-1/4)^2+[5*(3-5/2)-5]}

$$8 \times \{ ( 1 - \frac { 1 } { 4 } ) ^ { 2 } + [ 5 \cdot ( \frac { 3 - 5 } { 2 } ) - 5 ] \}$$

Evaluate

$$-\frac{151}{2}=-75.5$$

Solution Steps

Subtract \frac{1}{4} from 1 to get \frac{3}{4}.

$$8\left(\left(\frac{3}{4}\right)^{2}+5\times \frac{3-5}{2}-5\right)$$

Calculate \frac{3}{4} to the power of 2 and get \frac{9}{16}.

$$8\left(\frac{9}{16}+5\times \frac{3-5}{2}-5\right)$$

Subtract 5 from 3 to get -2.

$$8\left(\frac{9}{16}+5\times \frac{-2}{2}-5\right)$$

Divide -2 by 2 to get -1.

$$8\left(\frac{9}{16}+5\left(-1\right)-5\right)$$

Multiply 5 and -1 to get -5.

$$8\left(\frac{9}{16}-5-5\right)$$

Subtract 5 from \frac{9}{16} to get -\frac{71}{16}.

$$8\left(-\frac{71}{16}-5\right)$$

Subtract 5 from -\frac{71}{16} to get -\frac{151}{16}.

$$8\left(-\frac{151}{16}\right)$$

Multiply 8 and -\frac{151}{16} to get -\frac{151}{2}.

$$-\frac{151}{2}$$

Factor

$$-\frac{151}{2} = -75\frac{1}{2} = -75.5$$