Solve 8*5+729lfloor2rfloorleft|--5/frac{5{}}right|

$$8 \times 5+729 \lfloor 2 \rfloor \left| -- \frac{ 5 }{ \frac{ 5 }{ } } \right|$$

Evaluate

$$1498$$

Solution Steps

Multiply 8 and 5 to get 40.

$$40+729\lfloor 2\rfloor |-\left(-\frac{5}{\frac{5}{1}}\right)|$$

The floor of a real number a is the largest integer number less than or equal to a. The floor of 2 is 2.

$$40+729\times 2|-\left(-\frac{5}{\frac{5}{1}}\right)|$$

Multiply 729 and 2 to get 1458.

$$40+1458|-\left(-\frac{5}{\frac{5}{1}}\right)|$$

Divide 5 by \frac{5}{1} by multiplying 5 by the reciprocal of \frac{5}{1}.

$$40+1458|-\left(-\frac{5}{5}\right)|$$

Divide 5 by 5 to get 1.

$$40+1458|-\left(-1\right)|$$

The opposite of -1 is 1.

$$40+1458|1|$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of 1 is 1.

$$40+1458\times 1$$

Multiply 1458 and 1 to get 1458.

$$40+1458$$

Add 40 and 1458 to get 1498.

$$1498$$

Factor

$$2\times 7\times 107$$