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8\sqrt{3}-5\times 2\sqrt{3}+4\sqrt{7}s
Factor 12=2^{2}\times 3. Rewrite the square root of the product \sqrt{2^{2}\times 3} as the product of square roots \sqrt{2^{2}}\sqrt{3}. Take the square root of 2^{2}.
8\sqrt{3}-10\sqrt{3}+4\sqrt{7}s
Multiply -5 and 2 to get -10.
-2\sqrt{3}+4\sqrt{7}s
Combine 8\sqrt{3} and -10\sqrt{3} to get -2\sqrt{3}.