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8\sqrt{2}-4\times 2\sqrt{2}
Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.
8\sqrt{2}-8\sqrt{2}
Multiply -4 and 2 to get -8.
0
Combine 8\sqrt{2} and -8\sqrt{2} to get 0.