Evaluate
7\sqrt{2}+8\sqrt{19}-24\sqrt{3}\approx 3.201467103
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8\sqrt{19}+7\sqrt{2}-4\times 6\sqrt{3}
Factor 108=6^{2}\times 3. Rewrite the square root of the product \sqrt{6^{2}\times 3} as the product of square roots \sqrt{6^{2}}\sqrt{3}. Take the square root of 6^{2}.
8\sqrt{19}+7\sqrt{2}-24\sqrt{3}
Multiply -4 and 6 to get -24.
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