Solve 81/6+43/6=

$$8 \frac { 1 } { 6 } + 4 \frac { 3 } { 6 } =$$

Evaluate

$$\frac{38}{3}\approx 12.666666667$$

Solution Steps

Multiply 8 and 6 to get 48.

$$\frac{48+1}{6}+\frac{4\times 6+3}{6}$$

Add 48 and 1 to get 49.

$$\frac{49}{6}+\frac{4\times 6+3}{6}$$

Multiply 4 and 6 to get 24.

$$\frac{49}{6}+\frac{24+3}{6}$$

Add 24 and 3 to get 27.

$$\frac{49}{6}+\frac{27}{6}$$

Since \frac{49}{6} and \frac{27}{6} have the same denominator, add them by adding their numerators.

$$\frac{49+27}{6}$$

Add 49 and 27 to get 76.

$$\frac{76}{6}$$

Reduce the fraction \frac{76}{6} to lowest terms by extracting and canceling out 2.

$$\frac{38}{3}$$

Factor

$$\frac{2 \cdot 19}{3} = 12\frac{2}{3} = 12.666666666666666$$