Solve 81/4+6+33/8

$$8 \frac { 1 } { 4 } + 6 + 3 \frac { 3 } { 8 }$$

Evaluate

$$\frac{141}{8}=17.625$$

Solution Steps

Multiply 8 and 4 to get 32.

$$\frac{32+1}{4}+6+\frac{3\times 8+3}{8}$$

Add 32 and 1 to get 33.

$$\frac{33}{4}+6+\frac{3\times 8+3}{8}$$

Convert 6 to fraction \frac{24}{4}.

$$\frac{33}{4}+\frac{24}{4}+\frac{3\times 8+3}{8}$$

Since \frac{33}{4} and \frac{24}{4} have the same denominator, add them by adding their numerators.

$$\frac{33+24}{4}+\frac{3\times 8+3}{8}$$

Add 33 and 24 to get 57.

$$\frac{57}{4}+\frac{3\times 8+3}{8}$$

Multiply 3 and 8 to get 24.

$$\frac{57}{4}+\frac{24+3}{8}$$

Add 24 and 3 to get 27.

$$\frac{57}{4}+\frac{27}{8}$$

Least common multiple of 4 and 8 is 8. Convert \frac{57}{4} and \frac{27}{8} to fractions with denominator 8.

$$\frac{114}{8}+\frac{27}{8}$$

Since \frac{114}{8} and \frac{27}{8} have the same denominator, add them by adding their numerators.

$$\frac{114+27}{8}$$

Add 114 and 27 to get 141.

$$\frac{141}{8}$$

Factor

$$\frac{3 \cdot 47}{2 ^ {3}} = 17\frac{5}{8} = 17.625$$