Solve 81/3div11/4-22/3=

$$8 \frac { 1 } { 3 } \div 1 \frac { 1 } { 4 } - 2 \frac { 2 } { 3 } =$$

Evaluate

$$4$$

Solution Steps

Divide \frac{8\times 3+1}{3} by \frac{1\times 4+1}{4} by multiplying \frac{8\times 3+1}{3} by the reciprocal of \frac{1\times 4+1}{4}.

$$\frac{\left(8\times 3+1\right)\times 4}{3\left(1\times 4+1\right)}-\frac{2\times 3+2}{3}$$

Multiply 8 and 3 to get 24.

$$\frac{\left(24+1\right)\times 4}{3\left(1\times 4+1\right)}-\frac{2\times 3+2}{3}$$

Add 24 and 1 to get 25.

$$\frac{25\times 4}{3\left(1\times 4+1\right)}-\frac{2\times 3+2}{3}$$

Multiply 25 and 4 to get 100.

$$\frac{100}{3\left(1\times 4+1\right)}-\frac{2\times 3+2}{3}$$

Multiply 1 and 4 to get 4.

$$\frac{100}{3\left(4+1\right)}-\frac{2\times 3+2}{3}$$

Add 4 and 1 to get 5.

$$\frac{100}{3\times 5}-\frac{2\times 3+2}{3}$$

Multiply 3 and 5 to get 15.

$$\frac{100}{15}-\frac{2\times 3+2}{3}$$

Reduce the fraction \frac{100}{15} to lowest terms by extracting and canceling out 5.

$$\frac{20}{3}-\frac{2\times 3+2}{3}$$

Multiply 2 and 3 to get 6.

$$\frac{20}{3}-\frac{6+2}{3}$$

Add 6 and 2 to get 8.

$$\frac{20}{3}-\frac{8}{3}$$

Since \frac{20}{3} and \frac{8}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{20-8}{3}$$

Subtract 8 from 20 to get 12.

$$\frac{12}{3}$$

Divide 12 by 3 to get 4.

$$4$$

Factor

$$2^{2}$$