Solve 8div11/3+21/5*0.75

$$8 \div 1 \frac { 1 } { 3 } + 2 \frac { 1 } { 5 } \times 0.75$$

Evaluate

$$7.65$$

Solution Steps

Divide 8 by \frac{1\times 3+1}{3} by multiplying 8 by the reciprocal of \frac{1\times 3+1}{3}.

$$\frac{8\times 3}{1\times 3+1}+\frac{2\times 5+1}{5}\times 0.75$$

Multiply 8 and 3 to get 24.

$$\frac{24}{1\times 3+1}+\frac{2\times 5+1}{5}\times 0.75$$

Multiply 1 and 3 to get 3.

$$\frac{24}{3+1}+\frac{2\times 5+1}{5}\times 0.75$$

Add 3 and 1 to get 4.

$$\frac{24}{4}+\frac{2\times 5+1}{5}\times 0.75$$

Divide 24 by 4 to get 6.

$$6+\frac{2\times 5+1}{5}\times 0.75$$

Multiply 2 and 5 to get 10.

$$6+\frac{10+1}{5}\times 0.75$$

Add 10 and 1 to get 11.

$$6+\frac{11}{5}\times 0.75$$

Convert decimal number 0.75 to fraction \frac{75}{100}. Reduce the fraction \frac{75}{100} to lowest terms by extracting and canceling out 25.

$$6+\frac{11}{5}\times \frac{3}{4}$$

Multiply \frac{11}{5} times \frac{3}{4} by multiplying numerator times numerator and denominator times denominator.

$$6+\frac{11\times 3}{5\times 4}$$

Do the multiplications in the fraction \frac{11\times 3}{5\times 4}.

$$6+\frac{33}{20}$$

Convert 6 to fraction \frac{120}{20}.

$$\frac{120}{20}+\frac{33}{20}$$

Since \frac{120}{20} and \frac{33}{20} have the same denominator, add them by adding their numerators.

$$\frac{120+33}{20}$$

Add 120 and 33 to get 153.

$$\frac{153}{20}$$

Factor

$$\frac{17 \cdot 3 ^ {2}}{5 \cdot 2 ^ {2}} = 7\frac{13}{20} = 7.65$$