Solve 8*a^2*a^4*a^3*a^-9

$$8 \cdot a ^ { 2 } \times a ^ { 4 } \times a ^ { 3 } \times a ^ { - 9 }$$

Evaluate

$$8$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 2 and 4 to get 6.

$$8a^{6}a^{3}a^{-9}$$

To multiply powers of the same base, add their exponents. Add 6 and 3 to get 9.

$$8a^{9}a^{-9}$$

Multiply a^{9} and a^{-9} to get 1.

$$8$$

Factor

$$2^{3}$$