Solve 8^x-2=0

$$8 ^ { x } - 2 = 0$$

Solve for x

$$x=\frac{1}{3}\approx 0.333333333$$

Steps Using Definition of Logarithm

Use the rules of exponents and logarithms to solve the equation.

$$8^{x}-2=0$$

Add 2 to both sides of the equation.

$$8^{x}=2$$

Take the logarithm of both sides of the equation.

$$\log(8^{x})=\log(2)$$

The logarithm of a number raised to a power is the power times the logarithm of the number.

$$x\log(8)=\log(2)$$

Divide both sides by \log(8).

$$x=\frac{\log(2)}{\log(8)}$$

By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).

$$x=\log_{8}\left(2\right)$$

Solve for x (complex solution)

$$x=\frac{2\pi n_{1}i}{3\ln(2)}+\frac{1}{3}$$

$$n_{1}\in \mathrm{Z}$$