Solve 8^{2}*2^{2}-5^{5}:5^2-2^5*3+9^0*9-6^2

$$8 ^ { 2 } \cdot 2 ^ { 2 } - 5 ^ { 5 } : 5 ^ { 2 } - 2 ^ { 5 } \cdot 3 + 9 ^ { 0 } \cdot 9 - 6 ^ { 2 }$$

Evaluate

$$8$$

Solution Steps

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 2 from 5 to get 3.

$$8^{2}\times 2^{2}-5^{3}-2^{5}\times 3+9^{0}\times 9-6^{2}$$

To multiply powers of the same base, add their exponents. Add 0 and 1 to get 1.

$$8^{2}\times 2^{2}-5^{3}-2^{5}\times 3+9^{1}-6^{2}$$

Calculate 8 to the power of 2 and get 64.

$$64\times 2^{2}-5^{3}-2^{5}\times 3+9^{1}-6^{2}$$

Calculate 2 to the power of 2 and get 4.

$$64\times 4-5^{3}-2^{5}\times 3+9^{1}-6^{2}$$

Multiply 64 and 4 to get 256.

$$256-5^{3}-2^{5}\times 3+9^{1}-6^{2}$$

Calculate 5 to the power of 3 and get 125.

$$256-125-2^{5}\times 3+9^{1}-6^{2}$$

Subtract 125 from 256 to get 131.

$$131-2^{5}\times 3+9^{1}-6^{2}$$

Calculate 2 to the power of 5 and get 32.

$$131-32\times 3+9^{1}-6^{2}$$

Multiply 32 and 3 to get 96.

$$131-96+9^{1}-6^{2}$$

Subtract 96 from 131 to get 35.

$$35+9^{1}-6^{2}$$

Calculate 9 to the power of 1 and get 9.

$$35+9-6^{2}$$

Add 35 and 9 to get 44.

$$44-6^{2}$$

Calculate 6 to the power of 2 and get 36.

$$44-36$$

Subtract 36 from 44 to get 8.

$$8$$

Factor

$$2^{3}$$