Solve 8^2:[3^2-(20-3^3)]

$$8 ^ { 2 } : [ 3 ^ { 2 } - ( 20 - 3 ^ { 3 } ) ]$$

Evaluate

$$4$$

Solution Steps

Calculate 8 to the power of 2 and get 64.

$$\frac{64}{3^{2}-\left(20-3^{3}\right)}$$

Calculate 3 to the power of 2 and get 9.

$$\frac{64}{9-\left(20-3^{3}\right)}$$

Calculate 3 to the power of 3 and get 27.

$$\frac{64}{9-\left(20-27\right)}$$

Subtract 27 from 20 to get -7.

$$\frac{64}{9-\left(-7\right)}$$

The opposite of -7 is 7.

$$\frac{64}{9+7}$$

Add 9 and 7 to get 16.

$$\frac{64}{16}$$

Divide 64 by 16 to get 4.

$$4$$

Factor

$$2^{2}$$