Solve for a
a=-\frac{b}{2}-\frac{c}{4}+2
Solve for b
b=-\frac{c}{2}-2a+4
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4a+2b+c=8
Swap sides so that all variable terms are on the left hand side.
4a+c=8-2b
Subtract 2b from both sides.
4a=8-2b-c
Subtract c from both sides.
4a=8-c-2b
The equation is in standard form.
\frac{4a}{4}=\frac{8-c-2b}{4}
Divide both sides by 4.
a=\frac{8-c-2b}{4}
Dividing by 4 undoes the multiplication by 4.
a=-\frac{b}{2}-\frac{c}{4}+2
Divide 8-2b-c by 4.
4a+2b+c=8
Swap sides so that all variable terms are on the left hand side.
2b+c=8-4a
Subtract 4a from both sides.
2b=8-4a-c
Subtract c from both sides.
2b=8-c-4a
The equation is in standard form.
\frac{2b}{2}=\frac{8-c-4a}{2}
Divide both sides by 2.
b=\frac{8-c-4a}{2}
Dividing by 2 undoes the multiplication by 2.
b=-\frac{c}{2}-2a+4
Divide 8-4a-c by 2.
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