Solve 8=4*(-3)^3+2*(-3)^2+(5^3)-8

$$8 = 4 \cdot ( - 3 ) ^ { 3 } + 2 \cdot ( - 3 ) ^ { 2 } + ( 5 ^ { 3 } ) - 8$$

Verify

Solution Steps

Calculate -3 to the power of 3 and get -27.

$$8=4\left(-27\right)+2\left(-3\right)^{2}+5^{3}-8$$

Multiply 4 and -27 to get -108.

$$8=-108+2\left(-3\right)^{2}+5^{3}-8$$

Calculate -3 to the power of 2 and get 9.

$$8=-108+2\times 9+5^{3}-8$$

Multiply 2 and 9 to get 18.

$$8=-108+18+5^{3}-8$$

Add -108 and 18 to get -90.

$$8=-90+5^{3}-8$$

Calculate 5 to the power of 3 and get 125.

$$8=-90+125-8$$

Add -90 and 125 to get 35.

$$8=35-8$$

Subtract 8 from 35 to get 27.

$$8=27$$

Compare 8 and 27.

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