Solve 8:(3-5)-2*[-3*(1-4)-6:(1-3)]

$$8 : ( 3 - 5 ) - 2 \cdot [ - 3 \cdot ( 1 - 4 ) - 6 : ( 1 - 3 ) ]$$

Evaluate

$$-28$$

Solution Steps

Subtract 5 from 3 to get -2.

$$\frac{8}{-2}-2\left(-3\left(1-4\right)-\frac{6}{1-3}\right)$$

Divide 8 by -2 to get -4.

$$-4-2\left(-3\left(1-4\right)-\frac{6}{1-3}\right)$$

Subtract 4 from 1 to get -3.

$$-4-2\left(-3\left(-3\right)-\frac{6}{1-3}\right)$$

Multiply -3 and -3 to get 9.

$$-4-2\left(9-\frac{6}{1-3}\right)$$

Subtract 3 from 1 to get -2.

$$-4-2\left(9-\frac{6}{-2}\right)$$

Divide 6 by -2 to get -3.

$$-4-2\left(9-\left(-3\right)\right)$$

The opposite of -3 is 3.

$$-4-2\left(9+3\right)$$

Add 9 and 3 to get 12.

$$-4-2\times 12$$

Multiply 2 and 12 to get 24.

$$-4-24$$

Subtract 24 from -4 to get -28.

$$-28$$

Factor

$$-28$$