Solve 8+(-3)^2*(-2/3)-|-9|

$$8 + ( - 3 ) ^ { 2 } \times ( - \frac { 2 } { 3 } ) - | - 9 |$$

Evaluate

$$-7$$

Solution Steps

Calculate -3 to the power of 2 and get 9.

$$8+9\left(-\frac{2}{3}\right)-|-9|$$

Express 9\left(-\frac{2}{3}\right) as a single fraction.

$$8+\frac{9\left(-2\right)}{3}-|-9|$$

Multiply 9 and -2 to get -18.

$$8+\frac{-18}{3}-|-9|$$

Divide -18 by 3 to get -6.

$$8-6-|-9|$$

Subtract 6 from 8 to get 2.

$$2-|-9|$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -9 is 9.

$$2-9$$

Subtract 9 from 2 to get -7.

$$-7$$

Factor

$$-7$$